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11x-2x^2=-4
We move all terms to the left:
11x-2x^2-(-4)=0
We add all the numbers together, and all the variables
-2x^2+11x+4=0
a = -2; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·(-2)·4
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3\sqrt{17}}{2*-2}=\frac{-11-3\sqrt{17}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3\sqrt{17}}{2*-2}=\frac{-11+3\sqrt{17}}{-4} $
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